Question

An 8.7 g bullet is accelerated in a rifle barrel 105 cm long to a speed of 465 m/s. Use the work-energy theorem to find the average force exerted on the bullet while it is being accelerated. Answer in units of N.

Answer 1

Answer:896 N

Step-by-step explanation:

Given

mass of bullet
`m=8.7 gm`

Length of barrel
`d=105 cm=1.05 m`

final velocity
`v=465 m/s`

initial velocity
`u=0 m/s`

Work done by all the forces is equal to change in kinetic Energy

`F\cdot d=(1)/(2)* mv^2-0`

`F_(avg)* 1.05=(1)/(2)* 8.7* 10^(-3)* 465^2`

`F_(avg)=(0.5* 8.7* 10^(-3)* 465^2)/(1.05)`

`F_(avg)=895.789 Na\pprox 896 N`