Question

An apparatus like the one Cavendish used to find G has large lead balls that are 8.4 kg in mass and small ones that are 0.061 kg. The center of a large ball is separated by 0.057 m from the center of a small ball. Find the magnitude of the gravitational force between the masses if the value of the universal gravitational constant is 6.67259 × 10−11 Nm2/kg2

Answer 1

The gravitational force is
`1.05*10^(-8)\ N`

Step-by-step explanation:

Given that,

Mass of large ball = 8.4 kg

Mass of small ball = 0.061 kg

Separation = 0.057 m

Gravitational constant
`G= 6.67*10^(-11)\ Nm^2/kg^2`

We need to calculate the gravitational force

Using formula of gravitational force

`F= (Gm_(1)m_(2))/(r^2)`

Put the value into the formula

`F=(6.67259*10^(-11)*8.4*0.061)/((0.057)^2)`

`F=1.05*10^(-8)\ N`

Hence, The gravitational force is
`1.05*10^(-8)\ N`