Question

A bird is flying with a speed of 18.6 m/s over water when it accidentally drops a 2.30 kg fish. The acceleration of gravity is 9.81 m/s 2 . If the altitude of the bird is 5.50 m and air resistance is disregarded, what is the speed of the fish when it hits the water?

Answer 1

Answer:21.3 m/s

Step-by-step explanation:

Given

speed
`u=18.6 m/s`

mass of fish
`m_f=2.30 kg`

Altitude
`h=5.50 m`

Time taken to cover h

`h=ut+(at^2)/(2)`

`5.5=(9.8* t^2)/(2)`

`t^2=1.122`

`t=1.05 s`

Vertical velocity after
`t=1.05 s`

`v_y=0+gt`

`v_y=9.8* 1.05=10.38 m/s`

Horizontal velocity will remain same
`u=18.6 m/s`

Net velocity
`v_(net)=√(u^2+v_y^2)`

`v_(net)=√(18.6^2+10.38^2)`

`v_(net)=√(453.76)=21.30 m/s`