Question

A random sample of 65 bags of white cheddar popcorn​ weighed, on​ average, 5.74 ounces with a standard deviation of 0.26 ounce. Test the hypothesis that muequals5.8 ounces against the alternative​ hypothesis, muless than5.8 ​ounces, at the 0.10 level of significance.

Answer 1

We failed to accept null hypothesis

Explanation:

x= 5.74

Standard deviation =
`0.26`

`H_0:\mu = 5.8\\H_a:\mu < 5.8`

n = 65

We will use z test

Formula :
`z=(x-\mu)/((\sigma)/(√(n)))`

Substitute the values :

`z=(5.74-5.8)/((0.26)/(√(65)))`

`z=-1.86`

Refer the z table for p value

p value = 0.0314

α = 0.10

p value < α

So, we failed to accept null hypothesis