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5 votes
-12x2 + 45x + 12

A. – 12x2 + 45x + 12
-3(4x2 + 17x + 4)
-3(4x + 1)(x + 4)

B. -12x2 + 45x + 12
-3(4x2 - 15x – 4)
-3(4x + 1)(x – 4)

C. -12x2 + 45x + 12
-3(4x2 - 15x – 4)
-3(2x + 1)(2x - 4)

D. -12x2 + 45x + 12
-3(4x2 + 15x – 4)
-3(4x - 1)(x + 4)

User Nabbit
by
7.7k points

1 Answer

9 votes

Answer:

3(4x + 1)(x - 4) Answer choice B

Explanation:

-12x^2 + 45 + 12

You would take out the -3 in the equation.

-3(4x^2 -15x - 4)

You can then multiply the first 4 and the last -4 and get a -16. You can then find two numbers that would multiply to -16 and add to -15.

You would do this by listing the factors of -16, which the numbers 1 and -16 would work.

You would then substitute each value in for the 17x and add them together, which this is just separating the value 17x.

3(4x^2 - 16x + x - 4)

3(4x^2 - 16x)(x - 4)

You can then take ou ta four for the first function in the parentheses.

3(4x(x - 4) 1(x - 4))

Then you take the function from the outside and the inside.

3(4x + 1)(x - 4)

The answer to the question would be B.

User Hectorsq
by
7.9k points
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