The Americium nucleus, 241 95 Am, decays to a Neptunium nucleus, 237 93 Np, by emitting an alpha particle of mass 4.00260 u and kinetic energy 5.5 MeV. Estimate the mass of the …

Question

asked Dec 10, 2020 56.5k views

1 Answer

Jason Jones · Answer 1 · 2020-12-15T02:48:34+0000

Answer:

The mass of Neptunium is 237.054 u.

Step-by-step explanation:

Given that,

Mass of Americium = 241.05682 u

Mass of alpha particle = 4.00260 u

The equation is,

$_(95)^(241)Am\rightarrow _(93)^(237)NP+\alpha\ particle+5.5 MeV$

Let the mass of Neptunium is m.

Since the mass remain same.

We need to calculate the mass of Neptunium

Using formula of mass

Mass of Neptunium = Mass of Americium -Mass of alpha particle

Put the value into the formula

m=241.05682 -4.00260

$m=237.054\ u$

Hence, The mass of Neptunium is 237.054 u.