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A bicycle is traveling north at 5.0 m/s. The mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radius of 20 cm. What are the magnitude and direction of the angular momentum of the wheel about its axle?

User NinjaBoy
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1 Answer

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Answer:2

Step-by-step explanation:

Given

Velocity of bicycle is 5 m/s towards north

radius of rim
r=20 cm

mass of rim
m=2 kg

Angular momentum
\vec{L}=I\cdot \vec{\omega }


I=mr^2=2* 0.2^2=0.08 kg-m^2


\omega =(v)/(r)=(5)/(0.2)=25 rad/s


L=0.08* 25=2kg-m^2/s

direction of Angular momentum will be towards west

User Alexandre Ouicher
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