Question

A bicycle is traveling north at 5.0 m/s. The mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radius of 20 cm. What are the magnitude and direction of the angular momentum of the wheel about its axle?

Answer 1

Answer:2

Step-by-step explanation:

Given

Velocity of bicycle is 5 m/s towards north

radius of rim
`r=20 cm`

mass of rim
`m=2 kg`

Angular momentum
`\vec{L}=I\cdot \vec{\omega }`

`I=mr^2=2* 0.2^2=0.08 kg-m^2`

`\omega =(v)/(r)=(5)/(0.2)=25 rad/s`

`L=0.08* 25=2kg-m^2/s`

direction of Angular momentum will be towards west