Answer:0.829 to 0.853
Step-by-step explanation:
Given
height through ball is dropped

velocity at just before collision is



if the now if the ball rises to a height of 175 cm , velocity after collision to reach at that height is

if the ball rises to an height of 185 cm then velocity after collision

value of e for



e for 185 cm

Range of e is 0.829 to 0.853