Answer:
We conclude that the calibration point is set too high.
Explanation:
We are given the following in the question:
Population mean, μ = 1000 grams
Sample mean,
= 1001.1 grams
Sample size, n = 50
Alpha, α = 0.05
Population standard deviation, σ = 2.8 grams
First, we design the null and the alternate hypothesis

We use One-tailed(right) z test to perform this hypothesis.
Formula:

Putting all the values, we have

Now,

Since,

We reject the null hypothesis and accept the alternate hypothesis. We accept the alternate hypothesis. We conclude that the calibration point is set too high.