Question

A copper-constantan thermocouple generates a voltage of 4.75 x 10-3 volts when the temperature of the hot junction is 110 °C and the reference junction is kept at 0 °C. If the voltage is proportional to the difference in temperature between the junctions, what is the temperature in degrees Celsius of the hot junction when the voltage is 1.76 x 10-3 volts?

Answer 1

The temperature of the hot junction is 40.7°C.

Step-by-step explanation:

Given that,

Voltage
`V=4.75*10^(-3)\ volts`

Voltage
`V'=1.76*10^(-3)\ volt`

Temperature of hot junction = 110°C

If the voltage is proportional to the difference in temperature between the junctions,

We need to calculate the temperature of the hot junction

Using formula of temperature

`(V)/(V')=(\Delta T)/(\Delta T)`

`(V)/(V')=(T_(2)-T_(1))/(T_(2)-T_(1))`

Here,T₁=0°C

`(V)/(V')=(110)/(T_(2))`

Put the value into the formula

`(4.75*10^(-3))/(1.76*10^(-3))=(110)/(T_(2))`

`T_(2)=(110*1.76*10^(-3))/(4.75*10^(-3))`

`T_(2)=40.7^(\circ)C`

Hence, The temperature of the hot junction is 40.7°C.