Answer:
solution set = {5/3 , 14/3}
Explanation:
Given that:
y=4x-2 _________ eq1
y=x+3 ----------------- eq2
Subtracting eq 2 from eq1 we get:
0 = 3x - 5
By simplifying we get:
3x = 5
x = 5/3
Now putting value of x in eq2 we get:
y = 5/3 + 3
Taking LCM to make denominator same
y = 5/3 + 9/3
y = 14/3
So the solution set = {5/3 , 14/3}
i hope it will help you!