Question

Please help with that problem
Important İ have quiz tomorrow

Answer 1

Final pressure of the gas remaining in the first container is 3.5 atm

Step-by-step explanation:

Since it is given that temperature is constant , we can apply -

PV=constant , where

P = Pressure of the gas

V = Volume of the container in which the gas is contained

Initially,

For container 1 -

`P_(i)` = 4 atm

`V_(1)` = 6 L

Finally,

For container 2 -

`P_(f,2)` = 3 atm

`V_(2)` = 1 L

For container 1 -

`P_(f,1)` = ?

`V_(1)` = 6 L

∴
`P_(i)`
`V_(1)` =
`P_(f,1)`
`V_(1)` +
`P_(f,2)`
`V_(2)`

∴ 4×6 = (
`P_(f,1)`×6) +(3×1)

∴
`P_(f,1)` = 3.5 atm