Question

Claim: The mean pulse rate (in beats per minute, or bpm) of adult males is equal to 69 bpm. For the random sample of 153 adult males in Data Set 1 "Body Data" in Appendix B, the mean pulse rate is 69.6 bpm and the standard deviation is 11.3 bpm. Only identify the null and alternative hypothesis.

Answer 1

`H_0:\mu=69`

`H_a:\mu\\eq69`

Explanation:

We know that ,

Null hypothesis
`(H_0)` is a statement that contains the population parameter to represent claim or against claim statement along with = , ≤ and ≥ signs.

Where as Alternative hypothesis
`(H_a)` is also a statement that contains the population parameter but against the null hypothesis . It contains ≠ , < and > signs.

In the given situation, the population parameter is population mean
`(\mu)` .

Claim: The mean pulse rate (in beats per minute, or bpm) of adult males is equal to 69 bpm.

i.e.
`H_0:\mu=69`

and
`H_a:\mu\\eq69` [Against
`H_0`]