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During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the remaining apples. On the third hour he sold 25% of the remaining apples, and so on, selling 5% more each following hour.

b) If during the second hour 25.5 kg of apples were sold, how many kilograms of apples will be sold during the fourth hour of operation?

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Answer:

22.95 kg

Explanation:

Let's say the farm stand owner starts with x kg of apples.

During the first hour, he sells 15% of the apples:

0.15 x

This means he's left with 85% of the original apples. During the second hour, he sells 20% of the remaining apples:

0.20 (0.85 x)

= 0.17 x

He's sold a total of 15% + 17% = 32% of the apples, so he's left with 68% of the apples. Continuing the pattern, the apples sold during the third hour:

0.25 (0.68 x)

= 0.17 x

He's sold 49% of the apples and is left with 51%. The apples sold during the fourth hour:

0.30 (0.51 x)

= 0.153 x

If 0.17 x = 25.5, then x = 150. So the apples sold during the fourth hour is:

0.153 (150) = 22.95

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