Question

The asteroid Ceres has a mass 6.797 × 1020 kg and a radius of 472.9 km. What is g on the surface? The value of the universal gravitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of m/s 2 .

Answer 1

`g=0.20\ m/s^2`

Step-by-step explanation:

It is given that,

Mass of the asteroid Ceres,
`m=6.797* 10^(20)\ kg`

Radius of the asteroid,
`r=472.9\ km=472.9* 10^3\ m`

The value of universal gravitational constant,
`G=6.67259* 10^(-11)\ N.m^2/kg^2`

We know that the expression for the acceleration due to gravity is given by :

`g=(Gm)/(r^2)`

`g=(6.67259* 10^(-11)* 6.797* 10^(20))/((472.9* 10^3)^2)`

`g=0.20\ m/s^2`

So, the value of acceleration due to gravity on that planet is
`0.20\ m/s^2`. Hence, this is the required solution.