Question

Moe is carrying and supporting a large crate by exerting 1000 N. He is walking at constant velocity across a level, horizontal floor. If he covers a distance of 10 meters, how much work does he do on the crate? Use g = 10m/s2 if needed. Ignore friction between Moe and the crate.

Answer 1

The work done by Moe on the crate is 10,000 J.

Step-by-step explanation:

The work done by Moe on the crate can be calculated using the formula:

Work = Force x Distance x Cosine(theta)

Since Moe is exerting a force of 1000 N and the distance covered is 10 meters, we can plug these values into the formula:

Work = 1000 N x 10 m x Cosine(0°)

The angle theta is 0° because Moe is exerting a force in the same direction as the displacement.

Cosine(0°) is equal to 1, so the work done by Moe on the crate is:

Work = 1000 N x 10 m x 1 = 10,000 J

Answer 2

he did not work on the create

Step-by-step explanation:

Honestly I have no idea it makes a lot of sense to use the work equation so that was my first answer but for some reason on UT Quest it said that was the wrong and moe not doing any work on the create was the right answer