Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s). If a particular disk is spun at 646.1 rad/s while it is being read, and then is allowed to come to rest over 0.569 seconds, what is the magnitude of the average angular acceleration of the disk?

Answer 1

Angular acceleration will be
`1135.5rad/sec^2`

Step-by-step explanation:

We have given initial angular speed of a particular disk
`\omega _i=646.1rad/sec`

And it finally comes to rest so final angular speed
`\omega _f=0rad/sec`

Time is given as t = 0.569 sec

From third equation of motion we know that

`\omega _f=\omega _i+\alpha t`

So angular acceleration
`\alpha =(\omega _f-\omega _i)/(t)=(0-646.1)/(0.569)=1135.5rad/sec^2`