Answer:
Distance, y = -2.287 meters
Step-by-step explanation:
Given that,
The separation between tow buildings, d = 4 m
Velocity of the stuntman, v = 5 m/s
Angle with respect to the flat roof,

We know that the horizontal component of velocity is given by :

The velocity of an object is equal to the total displacement divided by total time taken as :

t is the time of flight


t = 0.828 seconds
Let he will fall to d distance of y. Using the second equation to find it as :

Here, a = -g

is the vertical component of velocity


y = -2.287 meters
So, he will fall at a distance of 2.287 meters. Hence, this is the required solution.