Answer:
P=0.61 or 61%
Explanation:
If we pick a random point within the circle, it can fall in the white area or in the pink area. Since the sum of both areas makes the sample space or the total area of the circle, we can compute the probabilities according to the ratio of the areas with respect to the total area, that is:

The area of the circle is

The area of both the triangles is

Where r=4 cm, b=3 cm, h= (4+2.5) cm = 6.5 cm
Then we have:


The white area is obtained by subtracting both areas

So the probability is
