Question

On an alien planet, an object moving at 4.0 m/s on the horizontal ground comes to rest after traveling a distance of 10 m. If the coefficient of kinetic friction between the object and the surface is 0.20, what is the value of g on that planet?

Answer 1

So acceleration due to gravity is
`4m/sec^2`

Step-by-step explanation:

We have given initial speed of the object u = 4 m/sec

As object finally comes to rest so final speed v = 0 m./sec

Distance traveled s = 10 m

From third equation of motion we know that
`v^2=u^2+2as`

`0^2=4^2+2* a* 10`

`a=-0.8m/sec^2`

Coefficient of kinetic friction
`\mu _k=0.2`

We know that relation between acceleration and coefficient of kinetic friction

`a=\mu _kg`

`g=(a)/(\mu _k)=(0.8)/(0.2)=4m/sec^2`

So acceleration due to gravity is
`4m/sec^2`