Answer: D .
![N(t) = 3 + (0.25t)^3 - 8(1.06)^t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y4lgjcl7rfg8m628pcspcbfwg06v21n7xg.png)
Explanation:
Given : Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is represented by the function,
![A(t) = 5 + (0.25t)^3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pcmorik2vzs74ony3ztzcv8wur7m9hzje5.png)
The number of bacteria of species B, B(t), after t hours is represented by the function,
![B(t) = 2 + 8(1.06)^t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2y0iwlb5pn10l2olemk2nfe2enbyo036s1.png)
Then, the difference in the number of bacteria, N(t), of both the species after t hours will be :-
![N(t)=A(t)-B(t)\\\\=5 + (0.25t)^3-(2 + 8(1.06)^t)\\\\=5 + (0.25t)^3-2-8(1.06)^t\\\\=5-2 +(0.25t)^3-8(1.06)^t\\\\=3+(0.25t)^3-8(1.06)^t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3n60qzt6kb71jnge1hzb5gerd96zoq4xm4.png)
Hence, the correct answer should be : D .
![N(t) = 3 + (0.25t)^3 - 8(1.06)^t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y4lgjcl7rfg8m628pcspcbfwg06v21n7xg.png)