The "magnitude of the torque" is "4.59375 Nm".
Step-by-step explanation:
The "gravitational force" on the "bob of the pendulum" is m × g
m = 0.75 kg
m = 0.75 × 9.8 = 7.35 N
The "torque of this force" around "the pivot" is given by the "vector product" of the "radial displacement vector" with "the force vector".
The "magnitude of this torque" is given by "r × F × sin A"
Where, r = the "radial distance" = 1.25 m
F = "gravitational force" = 7.35 N
Thus the "magnitude of the torque" is = 1.25 × 7.35 × sin30
The "magnitude of the torque" = 9.1875 × 0.5
The "magnitude of the torque" = 4.5375
Therefore, the "magnitude of the torque" is 4.59375 Nm