Question

A series RL circuit contains two resistors and two inductors. The resistors are 33 Ω and 47 Ω. The inductors have inductive reactances of 60 Ω and 30 Ω. The applied voltage is 120 V.

What is the voltage drop on the 33 Ω resistor?

Answer 1

Voltage across 33 ohm resistor is 33.886 volt

Step-by-step explanation:

We have given that there is RL circuit which contain two resistance and inductance

Resistance of two resistor
`R_1=33\Omega \ and\ R_2=47\Omega`

So equivalent resistance
`R=R_1+R_2=33+47=80\Omega`

Inductance of inductive reactance
`X_1=60\Omega \ and\ X_2=30\Omega`

So equivalent inductive reactance
`X=X_1+X_2=60+30=90\Omega`

Now equivalent impedance
`Z=R+JX=80+J90=√(80^2+90^2)=120.4159`

Voltage is given as
`V=120volt`

So current
`i=(V)/(Z)=(120)/(120.4159)=0.9965A`

So voltage across 33 ohm resistor
`V=iR=0.9965* 33=32.886volt`