Question

530 mL of CO gas at a pressure of 1.2 atm and a temperature of 17ºC. What is the volume of the gas at 0ºC and 1 atm?

Answer 1

598.74 mL

Step-by-step explanation:

Using Ideal gas equation for same mole of gas as

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

Given ,

V₁ = 530 mL

V₂ = ?

P₁ = 1.2 atm

P₂ = 1 atm

T₁ = 17 ºC

T₂ = 0 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (17 + 273.15) K = 290.15 K

T₂ = (0 + 273.15) K = 273.15 K

Using above equation as:

`\frac {{P_1}* {V_1}}{T_1}=\frac {{P_2}* {V_2}}{T_2}`

`\frac {{1.2}* {530}}{290.15}=\frac {{1}* {V_2}}{273.15}`

Solving for V₂ , we get:

V₂ = 598.74 mL