Question

Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this model compare to a model for the force of gravity?

Answer 1

The answer is C

Step-by-step explanation:

I did it on usatestprep and got it right

Answer 2

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Step-by-step explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force=
`(Gm_(1)m_(2) )/(r^(2))`

Coulombs's Law=
`(Kq_(1)q_(2) )/(r^(2))`