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6. The energy of a photon of light is given by E = hc/Where h = Planck's constant (6.626 x 10-34 Jsec), c = the speed of light (3 x 108 m/sec) and the wavelength of light.In photosystem I, P700 in
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6. The energy of a photon of light is given by E = hc/Where h = Planck's constant (6.626 x 10-34 Jsec), c = the speed of light (3 x 108 m/sec) and the wavelength of light.In photosystem I, P700 in its ground state has an E'o = 0.4 V. Excitation of P700 by a photon of 700 nm light alters E'o = -0.6 V. Calculate the energy in a photon of 700 nm light and compare it to the G of exciting the photosystem to understand the efficiency of energy capture during photosynthesis. Remember to convert the energy from a single photon of light to a mol of photons using Avogadro's number.

User Anirban Karak
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Answer:The answers are on the attachments.

Step-by-step explanation:

6. The energy of a photon of light is given by E = hc/Where h = Planck's constant-example-1
6. The energy of a photon of light is given by E = hc/Where h = Planck's constant-example-2
User RMPR
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