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How many moles are there if you have.
a. 6.80 x 1024 molecules of Ba(NO3)2

1 Answer

9 votes

Answer:

11.3 mol Ba(NO₃)₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

6.80 × 10²⁴ molecules Ba(NO₃)₂

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. Set up:
    \displaystyle 6.80 \cdot 10^(24) \ molecules \ Ba(NO_3)_2((1 \ mol \ Ba(NO_3)_2)/(6.022 \cdot 10^(23) \ molecules \ Ba(NO_3)_2))
  2. Multiply:
    \displaystyle 11.2919 \ mol \ Ba(NO_3)_2

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

11.2919 mol Ba(NO₃)₂ ≈ 11.3 mol Ba(NO₃)₂

User Bluehallu
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