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A 13.0 g wire of length L = 73.0 cm is suspended by a pair of flexible leads in a magnetic field of 0.410 T. What is the magnitude and direction of the current required to remove the tension in the supporting leads? (Indicate the direction with the sign of your answer. Take right to be positive.)

User Dzang
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1 Answer

1 vote

Answer:

a) I = 0.426A

Calculations for the Magnitude of the Current can be viewed on the image attached.

b) The direction of the current depends on the direction of the magnetic field.

A 13.0 g wire of length L = 73.0 cm is suspended by a pair of flexible leads in a-example-1
User KAmol
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