Question

Calculate the concentration of acetic acid in a buffer solution made from 3.00 mL of 0.50 M acetic acid and 7.00 mL of 0.50 sodium acetate.

Answer 1

Step-by-step explanation:

The given data is as follows.

`M_(initial)` = 0.50 M,
`V_(1)` = 3.00 ml

`V_(2)` = 7.00 ml,

Therefore, calculate the total volume as follows.

Total volume =
`V_(1) + V_(2)`

= 3.00 ml + 7.00 ml

= 10.0 ml

Now, calculate the no. of moles of acetic acid as follows.

No. of moles of acetic acid = molarity × volume in mL

= 3.0 × 0.50

= 1.5 mmoles

=
`1.5 * 10^(-3)` moles

(As 1 mole = 0.001 mmol)

Therefore, calculate the concentration of acetic acid as follows.

Concentration of the acetic acid =
`\text{number of moles} * \frac{1000}{\text{volume in mL}}`

=
`1.5 * 10^(-3) * (1000)/(10)`

= 0.15 M

Thus, we can conclude that the concentration of acetic acid in buffer solution is 0.15 M.

Answer 2

0.15 M

Step-by-step explanation:

Number of mili moles of acetic acid = molarity×volume in mL = 3.0×0.50 =

1.5 milimoles = 1.5×10^{-3} moles

Concentration of the acetic acid = number of moles×1000/volume in mL

= 1.5×10^{-3}×1000/10 = 0.15 M