Answer:
a. 475.14 Hz
b. 1959 Hz
c. 2341.53 Hz , 3053.34 Hz
Step-by-step explanation:
![f = (1)/(2\pi*√(C*L))](https://img.qammunity.org/2020/formulas/physics/college/l9uns8nvhyi2oz7dgbubkzd6xjf3qtwrqq.png)
a. smallest use the capacitive 4.2 uF + 6.0 uF = 10.2uF replacing:
![f = (1)/(2\pi*√(C*L))f=(1)/(2\pi*√(10.2uF*11mH))](https://img.qammunity.org/2020/formulas/physics/college/316c6hwzwoajy7lku0t2sdhbiiu70e9qcf.png)
![f = 475.14 Hz](https://img.qammunity.org/2020/formulas/physics/college/jkxmjlxhwa0kdawhtn0cgcxpqez16z729n.png)
b. second smallest use the capacitive 6 uF so:
![f = (1)/(2\pi*√(C*L))=f = (1)/(2\pi*√(6uF*11mH))](https://img.qammunity.org/2020/formulas/physics/college/rxqxu08bdcqqda72uwt2jf8rcaxwcwltjw.png)
![f = 1959Hz](https://img.qammunity.org/2020/formulas/physics/college/n6oajl3n1vv2kvmngwxzkg38agr63lzrbm.png)
c. second largest and largest oscillation first combination so:
Use 4.2 uF
![f = (1)/(2\pi*√(C*L))=f = (1)/(2\pi*√(4.2uF*11mH))](https://img.qammunity.org/2020/formulas/physics/college/3dtzisua74n6lwznd7rib10bmw6zuhiwht.png)
![f = 2341.53 Hz](https://img.qammunity.org/2020/formulas/physics/college/h9ce88auaaotx5vccvp80s9agcruxkxgnz.png)
And finally largest oscillation cap in serie so:
![C=(c_1*c_2)/(c_1+c_2)=(4.2uF*6.0uf)/(4.2uf+6.0uF)](https://img.qammunity.org/2020/formulas/physics/college/pdehgpd4r0l05cdfbiys7ioffc1g9ovs6u.png)
![C=2.47 uF](https://img.qammunity.org/2020/formulas/physics/college/2n24trrw46jijvp2fx8pjdc05gwaf3n94t.png)
![f = (1)/(2\pi*√(C*L))=f = (1)/(2\pi*√(2.47uF*11mH))](https://img.qammunity.org/2020/formulas/physics/college/nfpvf7g37q3uu12da4wp5ocn5q36o9ut67.png)
![f = 3053.34 Hz](https://img.qammunity.org/2020/formulas/physics/college/5fk9gduetu62g1lunc8en0tv786sv1iscs.png)