Question

What is the value of sin(t) if cos(t)=0.1, and t is in quadrant 1

Answer 1

`sin(t)=(√(99))/(10)`

Explanation:

Remember that

If angle t belong to the First Quadrant

then

The value of sin(t) and cos(t) are positive values

we know that

`sin^2(t)+cos^2(t)=1` ---> by trigonometric identity

we have

`cos(t)=0.1=(1)/(10)`

substitute

`sin^2(t)+((1)/(10))^2=1`

`sin^2(t)+(1)/(100)=1`

`sin^2(t)=1-(1)/(100)`

`sin^2(t)=(99)/(100)`

`sin(t)=(√(99))/(10)`