Question

One mole of an ideal gas does 2100 J of work as it expands isothermally to a final pressure 1.00 x 10^5Pa and volume of 0.025m^3A) what was the initial volume of the gas, in cubic meters?B) what is the temperature of the gas, in kelvin?

Answer 1

(A) 0.004 m^3

(B) 48.11 K

Step-by-step explanation:

Work, W = 2100 J

Pressure, P = 1 x 10^5 Pa

V2 = 0.025 m^3

(A) let the initial volume of the gas is V1.

W = P (V2 - V1)

2100 = 1 x 10^5 (0.025 - V1)

0021 = 0.025 - V1

V1 = 0.025 - 0.021

V1 = 0.004 m^3

Thus, the initial volume of the gas is 0.004 m^3.

(B) Let the temperature of the gas is T

Use ideal gas equation

P1 x V1 = n x R T

1 x 10^5 x 0.004 = 1 x 8.314 x T

T = 48.11 K

Thus, the initial temperature of the gas is 48.11 K.