Question

A linearly polarized electromagnetic wave has an average intensity of I0. This wave is incident on a polarizer. What angle between the axis of polarization of the polarizer and the direction of polarization of the incident light will result in an average intensity of light leaving the polarizer of 0.13·I0?

Answer 1

θ = 68.9º

Step-by-step explanation:

The equation that governs the process of light passing through a polarizer is described by Malus's law

I = I₀ cos² θ

Where I is the transmitted intensity, I₀ is the incident intensity and TE is the angle between the light and the polarizer

If i is 0.13I₀, we substitute in the equation

0.13 Io = I₀ cos² θ

Cos² θ = 0.13

Cos θ = √ 0.13

θ = cos⁻¹ (0.36056)

θ = 68.9º