59.1k views
2 votes
At what speed, as a fraction of c, does a moving clock tick at four fifth the rate of an identical clock at rest?

User Hubcaps
by
7.1k points

1 Answer

5 votes

Answer:

The seed as a fraction of the speed of light is
(3)/(5)c

Solution:

As per the question:

Suppose,
t_(i) be the rate of an identical clock between two time intervals.

For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:

t =
(5)/(4)t_(i)

Now,

Using the relation of time dilation, from Einstein's relation:


t = \frac{t_(i)}{\sqrt{1 - (v^(2))/(c^(2))}}


(5)/(4)t_(i) = \frac{t_(i)}{\sqrt{1 - (v^(2))/(c^(2))}}

Squaring both sides:


((5)/(4))^(2) = (\frac{1}{\sqrt{1 - (v^(2))/(c^(2))}})^(2)


(25)/(16) = \frac{1}{{1 - (v^(2))/(c^(2))}}


1 - (16)/(25) = (v^(2))/(c^(2))


(v)/(c) = \sqrt{(9)/(25)}


(v)/(c) = (3)/(5)


v = (3)/(5)c

User Ndori
by
7.6k points