Question

What are the dimensions of the lightest​ open-top right circular cylindrical can that will hold a volume of 2744 cmcubed3​?

Answer 1

r=2.808cm h = 100cm

then we get volume of cylinder that is 2744 As explained below

Explanation:

Volume of cylinder = πr²h

Surface area of cylinder = 2πrh +πr² (1)

h= 2744 /πr²

put value oh h in equation (1)

Area =[2πr] 2744 /πr²

=[5488/r +πr²]

dA/dx=0

i.e 2πr=5488/r²

Solving this r.r= ∛5488/2π

=2.808

taking second derivation we get 100