Question

If the intensity level by 15 identical engines in a garage is 100 dB, what is the intensity level generated by each one of these engines?

a) 44 dB
b) 67 dB
c) 13 dB
d) 88 dB

Answer 1

To develop this problem it is necessary to apply the concepts related to Sound Intensity.

By definition the intensity is given by the equation

`\beta = 10Log((I)/(I_0))`

Where,

I = Intensity of Sound

`I_0`= Intensity of Reference

At this case we have that 15 engines produces 15 times the reference intensity, that is

`I= 15I_0`

And the total mutual intensity is 100 dB, so we should

`\beta = 100-10*log((15I_0)/(I_0))`

`\beta = 100-10*log(15)`

`\beta = 100-11.76`

`\beta = 88.23dB`

Therefore each one of these engines produce D. 88dB.