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Find the y intersept of

y=logbase (b)(a-k) based on the constants b and k ?

User Chamon Roy
by
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1 Answer

3 votes

Answer:


(0, log_(b)(-k)), k < 0

Explanation:


y = \log_(b)(a - k)

To find the y-intercept, set a = 0 and solve for y.


y = \log_(b)(0 - k)\\y = \log_(b)(-k)

This equation is undefined for k ≥ 0.

There is a y-intercept only if k < 0. Only then can the argument of the log function be positive.

The y-intercept is at


\mathbf{(0, log_(b)(-k)), k < 0}

For example, if b = 2 and k = -3, log₂(3) = 1.585

The intercept is at (0, 1.585).

Find the y intersept of y=logbase (b)(a-k) based on the constants b and k ?-example-1
User Red M
by
9.3k points

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