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When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of static friction between the car and the road is 0.88. Assuming your car doesnt
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When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of static friction between the car and the road is 0.88. Assuming your car doesnt skid, what is the force exerted on it by static friction?

User Zeokav
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1 Answer

4 votes

Answer:

Ff = 6058.5N

Step-by-step explanation:

The sum of forces is:


Ff = m*a_c


Ff = m*V^2/R


Ff = 1900*13^2/53


Ff = 6058.5N

User TALE
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