Answer:
Part 1) The lateral area is

Part 2) The surface area is

so
lateral area = 210 cm2; surface area = 325.5 cm2
Explanation:
Part 1) Find the lateral area of the regular hexagonal pyramid
The lateral area is equal to the area of its six triangular faces
so
![LA=6[(1)/(2)bh]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/blufoh6t7r2hvgxvka6bhqknnos4slue96.png)
we have

substitute
![LA=6[(1)/(2)(7)(10)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uogc0wflni0n743axoko7w6eyms71lpzc6.png)

Part 2) Find the surface area of the regular hexagonal pyramid
The surface area is equal to the lateral area plus the area of the hexagonal base
so

where
B is the area of the hexagonal base
Find the area of the hexagonal base
The area of the regular hexagon is equal to the area of six equilateral triangles
![B=6[(1)/(2)(b)(h)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g87p5mcl3jpsos4em79qhjnk5y7kcyj247.png)
we have

substitute
![B=6[(1)/(2)(7)(5.5)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i1cybfu7e2bn0omts0uop3ys0q4r4bment.png)

The surface area is equal to
