Answer:
Option C has correct equations.
Explanation:
Given that:
x + 2y = 2 ---------eq1
-4x + 4y = -8 ---------- eq2
eq2 can also be written after taking 2 common as
-x + y = -2 ----------- eq3
Now by adding eq 1 and eq3 we get:
3y = 0
OR
y=0
putting value of y in eq1
x + 0 = 2
x = 2
So the solution set = (2 , 0)
Now by putting values in equations of option C:
x + 2y = 2
2 + 2(0) = 2
2 = 2 (satisfied)
5x - 2y = 10
5(2) - 2(0) = 10
10 = 10 (satisfied)
i hope it will help you!