Answer:
C. 6.670
Step-by-step explanation:
Given data,
The resistance of the resistors, R₁, R₂, R₃ = 20 Ω
The potential difference of the battery, V = 12 V
The formula for resistors connected in parallel,
1/R = 1/R₁ + 1/R₂ + 1/R₃
Substituting the values,
1/R = 1/20 + 1/20 + 1/20
R = 6.67 Ω
Hence, the effective resistance in parallel connection, R = 6.67 Ω