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Factorise Fully 6(x-3)² + 24(x-3)​
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2 votes
Factorise Fully



6(x-3)² + 24(x-3)​

User Tim Pietzcker
by
5.8k points

2 Answers

6 votes

6·(x - 3)² + 24·(x - 3)​ =

= 6·(x - 3)(x - 3) + 24·(x - 3)

= 6·(x - 3)·(x - 3 + 4)

= 6·(x - 3)·(x + 1)

User Mininoz
by
5.2k points
1 vote

Answer:

6(x - 3)(x + 1)

Explanation:

Given

6(x - 3)² + 24(x - 3) ← factor out 6(x - 3) from each term

= 6(x - 3) [ x - 3 + 4 ]

= 6(x - 3)(x + 1) ← in factored form

User Newalp
by
5.4k points
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