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What is the student's kinetic energy at the bottom of the hill if he is moving at 18 m/s? Variables: Show Work
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9 votes
What is the student's kinetic energy at the bottom of the hill if he is moving

at 18 m/s?
Variables:
Show Work

User Out
by
5.2k points

1 Answer

4 votes

Answer:

KE = 10530 J or 10.53 KJ

Step-by-step explanation:

The formula for kinetic energy is KE = 1/2 mv^2

Let's apply the formula:

KE = 1/2 mv^2

KE = 1/2 (65kg) (18m/s)^2

KE = 10530 J or 10.53 KJ

User Ahdee
by
5.4k points
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