Question

For the reaction, calculate how many grams of the product form when 14.4 g of Br2 completely reacts. Assume that there is more than enough of the other reactant. 2K(s)+Br2(l)→2KBr(s)

Answer 1

The answer to your question is 21.45 g of KBr

Step-by-step explanation:

Chemical reaction

2K + Br₂ ⇒ 2KBr

14.4 ?

Process

1.- Calculate the molecular mass of bromine and potassium bromide

Bromine = 2 x 79.9 = 159.8g

Potassium bromide = 2(79.9 + 39.1) = 238 g

2.- Solve it using proportions

159.8 g of Bromine ------------ 238 g of potassium bromide

14.4 g of Bromine ------------ x

x = (14.4 x 238) / 159.8

x = 3427.2 / 159.8

x = 21.45g of KBr