Answer:
11.48 m
Step-by-step explanation:
initial velocity (u) = 15 m/s
acceleration due to gravity (g) = 9.8 m/s
final velocity (v) = 0 ( the ball's speed reduces gradually when thrown until
becomes 0 at maximum height)
find the height reached.
- height (s) = ut + 0.5 at^{2}
we cannot apply this formula directly because we do no know the time
(t), so we first need to find the time
0 = 15 + (-9.8 x t) (the negative sign is because the ball is decelerating
upwards)
15 = 9.8t
t = 1.53 s
- now that we have the time we can put it into the initial equation
- height (s) = ut + 0.5 at^{2}
height (s) = (15 x 1.53) + (0.5 x (-9.8) x 1.53^{2})
height = 22.95 - 11.47 = 11.48 m