Answer:
The sound level will be 1.870 dB louder.
Step-by-step explanation:
Given that,
Power = 130 W
Power = 200 W
We need to calculate the sound level
Using formula of sound level
![I_(dB)=10\log((I)/(I_(0)))](https://img.qammunity.org/2020/formulas/physics/college/w8m4h0zmigpfjep46rr59dgt7l9f9gr72k.png)
For one amplifier,
...(I)
For other amplifier,
...(II)
For difference in dB levels
![I_(2)-I_(1)=10\log((200)/(I_(0)))-10\log((130)/(I_(0)))](https://img.qammunity.org/2020/formulas/physics/college/5esv3q7fz4bh2rtjm7zx3w1ij4z60fimrq.png)
![I_(2)-I_(1)=10\log((200)/(I_(0))*(I_(0))/(130))](https://img.qammunity.org/2020/formulas/physics/college/1gn1muqpte1ietwvsaxspkkduow6n4oq6i.png)
![I_(2)-I_(1)=10\log((200)/(130))](https://img.qammunity.org/2020/formulas/physics/college/evprsfx018cgyohpuk0nvl4jn446sp61di.png)
![I_(2)-I_(1)=1.870\ dB](https://img.qammunity.org/2020/formulas/physics/college/qsup33eccu9gsi0dl0fgmxzevthkwbxgsu.png)
Hence, The sound level will be 1.870 dB louder.