Question

Which number can each term of the equation be multiplied by to eliminate the fractions before solving? 6 – x + = 6 minus StartFraction 3 Over 4 EndFraction x plus StartFraction 1 Over 3 EndFraction equals StartFraction one-half EndFraction x plus 5.x + 5 2 3 6 12

Answer 1

D

Step-by-step explanation:

Answer 2

We need to multiply 12 to each term to eliminate fractions.

Step-by-step explanation:

Given expression:

`6-(3)/(4)x+(1)/(3)=(1)/(2)x+5`

To eliminate the fraction we need to multiply each term by least common multiple of the denominators of the fraction.

The denominators in the above expressions are:

4, 3 and 2

The multiples of each can be listed below.

2⇒ 2,4,6,8,10,12,14,16.....

3⇒ 3,6,9,12,15,18

4⇒ 4,8,12.......

From the list of the multiples stated, we can see the least common multiple is 12.

So we will multiply each term by 12.

Multiplying 12 to both sides.

`12(6-(3)/(4)x+(1)/(3))=12((1)/(2)x+5)`

Using distribution,

`72-9x+4=6x+60`

Thus we successfully eliminated the fractions.