Question

A block slides with no friction and hits a spring with spring constant k=2000 N/m. The block compresses the spring in a straight line for a distance 0.15m. The block’s kinetic energy, in J, at that point is 0 J. What was its initial kinetic energy, in Joules?

Answer 1

To solve this exercise it is necessary to apply the concepts related to kinetic energy in a spring.

By definition the kinetic energy keeping what is stipulated in the stable Hooke law that

`KE_s = (1)/(2) kx^2`

Where,

K = Spring constant

x = Displacement

Our values are given as,

x = 0.15m

k = 2000N/m

Therefore replacing

`KE_s = (1)/(2) kx^2`

`KE_s = (1)/(2) (2000)(0.15)^2`

`KE_s = 22.5J`

Therefore the initial kinetic energy is 22.5J