Answer:
D. 1.5
Explanation:
One basic property you need to keep in mind while solving theses type of questions is as follows :
The length of tangents from an external point on a circle are equal. For simplicity a figure illustrating this property is attached.
- Length of RS = 6 ; Length of AS = RS - AR = 6-x
Consider S as external point and tangents as SA and SB, so SB=SA=6-x
- Length of ST = 9 ; Length of TB = ST - SB = 9 - (6-x) = 3+x
Consider T as external point and tangents as TB and TC, so TC=TB=3+x
- Length of TU = 7 ; Length of UC = TU - TC = 7 - (3+x) = 4-x
Consider U as external point and tangents as UC and UD, so UD=UC=4-x
- Length of UV = 15 ; Length of VD = UV - UD = 15 - (4-x) = 11+x
Consider V as external point and tangents as VD and VE, so VE=VD=11+x
- Length of VR = 14 ; Length of RE = VR - VE = 14 - (11+x) = 3-x
Now, Consider R as external point and tangents as RA and RE, so
RA = RE
x = 3 - x
2x = 3
x =
![(3)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/85tww783zdtzzps1k74cyql3cl3s1y42ha.png)
x = 1.5