Question

Wil-E- Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is 132m high. What is its impact velocity?​

Answer 1

Velocity impact is 50.86 m/s.

Step-by-step explanation:

If an "object of mass" "m" is dropped from "height" "h", then the "velocity" just before impact is "v" . The "kinetic energy" before impact is equal to its "gravitational potential energy" at the height from which it was dropped: Kinetic energy = J.

`\mathrm{v}^(2)=2 \mathrm{gh}`

V is impact velocity

h height in meter = 132 m

`\text { (gis referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^(2) \text { on Earth }`

`\mathrm{V}^(2)=2 * 9.8 * 132`

`V^(2)=19.6 * 132`

`V^(2)=2587.2`

`V=√(2587.2)`

V = 50.86 m/s

Velocity impact is 50.86 m/s.